Three Dimensional Geometry

Class 12 · Mathematics · 25 Questions

1intermediate🔧 Apply4 marksShort Answer

If a line makes angles 90∘,135∘,45∘90^\circ, 135^\circ, 45^\circ with the x,yx, y and zz-axes respectively, find its direction cosines.

2intermediate🔧 Apply4 marksShort Answer

Find the direction cosines of a line which makes equal angles with the coordinate axes.

3beginner🔧 Apply2 marksVery Short

If a line has the direction ratios −18,12,−4-18, 12, -4, then what are its direction cosines?

4intermediate🔧 Apply4 marksShort Answer

Show that the points (2,3,4),(−1,−2,1),(5,8,7)(2, 3, 4), (-1, -2, 1), (5, 8, 7) are collinear.

5intermediate🔧 Apply4 marksShort Answer

Find the direction cosines of the sides of the triangle whose vertices are (3,5,−4),(−1,1,2)(3, 5, -4), (-1, 1, 2) and (−5,−5,−2)(-5, -5, -2).

1intermediate🔧 Apply4 marksShort Answer

Show that the three lines with direction cosines 1213,−313,−413;413,1213,313;313,−413,1213\frac{12}{13}, \frac{-3}{13}, \frac{-4}{13}; \frac{4}{13}, \frac{12}{13}, \frac{3}{13}; \frac{3}{13}, \frac{-4}{13}, \frac{12}{13} are mutually perpendicular.

2intermediate🔧 Apply4 marksShort Answer

Show that the line through the points (1,−1,2),(3,4,−2)(1, -1, 2), (3, 4, -2) is perpendicular to the line through the points (0,3,2)(0, 3, 2) and (3,5,6)(3, 5, 6).

3intermediate🔧 Apply4 marksShort Answer

Show that the line through the points (4,7,8),(2,3,4)(4, 7, 8), (2, 3, 4) is parallel to the line through the points (−1,−2,1),(1,2,5)(-1, -2, 1), (1, 2, 5).

4intermediate🔧 Apply4 marksShort Answer

Find the equation of the line which passes through the point (1,2,3)(1, 2, 3) and is parallel to the vector 3i^+2j^−2k^3\hat{i} + 2\hat{j} - 2\hat{k}.

5intermediate🔧 Apply4 marksShort Answer

Find the equation of the line in vector and in cartesian form that passes through the point with position vector 2i^−j+4k^2\hat{i} - j + 4\hat{k} and is in the direction i^+2j^−k^\hat{i} + 2\hat{j} - \hat{k}.

6intermediate🔧 Apply4 marksShort Answer

Find the cartesian equation of the line which passes through the point (−2,4,−5)(-2, 4, -5) and parallel to the line given by x+33=y−45=z+86\frac{x+3}{3} = \frac{y-4}{5} = \frac{z+8}{6}.

7beginner💡 Understand2 marksVery Short

The cartesian equation of a line is x−53=y+47=z−62\frac{x-5}{3} = \frac{y+4}{7} = \frac{z-6}{2}. Write its vector form.

8intermediate🔧 Apply4 marksShort Answer

Find the angle between the following pairs of lines:

9intermediate🔧 Apply4 marksShort Answer

Find the angle between the following pair of lines:

10intermediate🔧 Apply4 marksShort Answer

Find the values of pp so that the lines 1−x3=7y−142p=z−32\frac{1-x}{3} = \frac{7y-14}{2p} = \frac{z-3}{2} and 7−7x3p=y−51=6−z5\frac{7-7x}{3p} = \frac{y-5}{1} = \frac{6-z}{5} are at right angles.

11intermediate🔧 Apply4 marksShort Answer

Show that the lines x−57=y+2−5=z1\frac{x-5}{7} = \frac{y+2}{-5} = \frac{z}{1} and x1=y2=z3\frac{x}{1} = \frac{y}{2} = \frac{z}{3} are perpendicular to each other.

12intermediate🔧 Apply4 marksShort Answer

Find the shortest distance between the lines r⃗=(i^+2j^+k^)+λ(i^−j^+k^)\vec{r} = (\hat{i} + 2\hat{j} + \hat{k}) + \lambda(\hat{i} - \hat{j} + \hat{k}) and r⃗=2i^−j^−k^+μ(2i^+j^+2k^)\vec{r} = 2\hat{i} - \hat{j} - \hat{k} + \mu(2\hat{i} + \hat{j} + 2\hat{k})

13intermediate🔧 Apply4 marksShort Answer

Find the shortest distance between the lines x+17=y+1−6=z+11\frac{x+1}{7} = \frac{y+1}{-6} = \frac{z+1}{1} and x−31=y−5−2=z−71\frac{x-3}{1} = \frac{y-5}{-2} = \frac{z-7}{1}

14intermediate🔧 Apply4 marksShort Answer

Find the shortest distance between the lines whose vector equations are r⃗=(i^+2j^+3k^)+λ(i^−3j^+2k^)\vec{r} = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda(\hat{i} - 3\hat{j} + 2\hat{k}) and r⃗=4i^+5j^+6k^+μ(2i^+3j^+k^)\vec{r} = 4\hat{i} + 5\hat{j} + 6\hat{k} + \mu(2\hat{i} + 3\hat{j} + \hat{k})

15advanced🔧 Apply4 marksShort Answer

Find the shortest distance between the lines whose vector equations are r⃗=(1−t)i^+(t−2)j^+(3−2t)k^\vec{r} = (1-t)\hat{i} + (t-2)\hat{j} + (3-2t)\hat{k} and r⃗=(s+1)i^+(2s−1)j^−(2s+1)k^\vec{r} = (s+1)\hat{i} + (2s-1)\hat{j} - (2s+1)\hat{k}

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