Show that the points are collinear.
Let A = (2, 3, 4), B = (-1, -2, 1), C = (5, 8, 7).
Direction ratios of AB: -1 - 2 = -3, -2 - 3 = -5, 1 - 4 = -3 So, direction ratios of AB are -3, -5, -3.
Direction ratios of BC: 5 - (-1) = 6, 8 - (-2) = 10, 7 - 1 = 6 So, direction ratios of BC are 6, 10, 6.
Checking proportionality: -3/6 = -1/2, -5/10 = -1/2, -3/6 = -1/2
The direction ratios of AB and BC are proportional, hence AB is parallel to BC. But point B is common to both AB and BC. Therefore, A, B, C are collinear points.
Explanation
Following the method shown in Example 5 of the textbook, we prove collinearity by showing that direction ratios of consecutive line segments are proportional. When direction ratios are proportional, the lines are parallel. If two lines share a common point and are parallel, they must lie on the same straight line, making the points collinear.
Solution Steps
Step 1: Label the points as A(2,3,4), B(-1,-2,1), C(5,8,7)
Step 2: Find direction ratios of AB: (-3, -5, -3)
Step 3: Find direction ratios of BC: (6, 10, 6)
Step 4: Verify proportionality: all ratios equal -1/2
Step 5: Conclude collinearity since AB ∥ BC with common point B