Try to explain why the average of two rational numbers and , which equals , is always a rational number between and .
The average of two rational numbers and is . Since and are rational, their sum is also a rational number by the rules of addition of rational numbers. Dividing this sum by 2 (a non-zero rational number) using the rules of division yields another rational number, .
Furthermore, this average always lies between and . If , adding to both sides gives , which simplifies to . Similarly, adding to both sides of gives , which simplifies to .
Therefore, is always a rational number strictly between and , illustrating the density of rational numbers.
Explanation
The textbook explains that rational numbers are dense, meaning between any two rational numbers, there is always another. By taking the average, we perform addition (which results in a rational number) and division by a non-zero rational number (which also results in a rational number). Algebraically, the average must fall between the two numbers because it is equidistant from both on the number line.
Solution Steps
Step 1: State that the sum a+b is rational because rational numbers are closed under addition.
Step 2: State that dividing (a+b) by 2 gives a rational number because rational numbers are closed under division by non-zero rational numbers.
Step 3: Show algebraically that if a < b, then a < (a+b)/2 < b, proving it lies between a and b.