Question 2 of 43intermediate🔍 AnalyzeShort Answer2 marks

What can you say about a and b if (a + b)^2 < a2a^{2} + b2b^{2}?

Correct Answer

a and b must have opposite signs (i.e., their product ab is negative, meaning one is positive and the other is negative).

Exercise: Think and Reflect | Q: 1 | (Page 4)
For More Understanding

Explanation

The textbook context provides the identity (a + b)^2 = a2a^{2} + 2ab + b2b^{2} and prompts the student to use the expansion to compare (a + b)^2 and a2a^{2} + b2b^{2}. By substituting the expansion into the inequality (a + b)^2 < a2a^{2} + b2b^{2}, we get a2a^{2} + 2ab + b2b^{2} < a2a^{2} + b2b^{2}, which simplifies to 2ab < 0. Thus, ab < 0, meaning a and b have opposite signs.

Solution Steps

  1. Step 1: Write the identity (a + b)^2 = a2a^{2} + 2ab + b2b^{2}.

  2. Step 2: Substitute the expansion into the inequality: a2a^{2} + 2ab + b2b^{2} < a2a^{2} + b2b^{2}.

  3. Step 3: Simplify the inequality by subtracting a2a^{2} + b2b^{2} from both sides to get 2ab < 0, or ab < 0.

  4. Step 4: Conclude that since ab < 0, a and b must have opposite signs (one positive, one negative).