Using the identities $(x+a)(x+b) = x^2 + (a+b)x + ab$ and $(ax+b)(cx+d) = acx^2 + (ad+bc)x + bd$ provided in the chapter, we can find the missing factors by comparing coefficients. For (i), we need two numbers that add to -11 and multiply to 24, which are -3 and -8. For (ii), expanding $(ax+b)(x+1)$ and comparing to $3x^2 - 4x - 7$ gives $a=3, b=-7$. For (iii), expanding $(2x-a)(bx+2)$ and comparing to $10x^2 - 11x - 6$ gives $a=3, b=5$. For (iv), finding factors of 6 and 2 that give a cross-sum of 7 yields $(2x+1)$ and $(3x+2)$.