Question 7 of 43intermediate🔧 ApplyShort Answer6 marks

Factor completely:

(i)

9x29x^{2} + 24xy + 16y216y^{2}

Answer

(3x + 4y)^2

(ii)

4s24s^{2} + 20st + 25t225t^{2}

Answer

(2s + 5t)^2

(iii)

49x249x^{2} + 28xy + 4y24y^{2}

Answer

(7x + 2y)^2

(iv)

64p264p^{2} + 32/3 pq + 4/9 q2q^{2}

Answer

(8p + 2/3 q)^2

(v)

3a23a^{2} + 4ab + 4/3 b2b^{2} (Hint: 2 was taken out as a common factor in Example 7. Is it possible to do something similar in Exercises (v) and (vi) above?)

Answer

1/3(3a + 2b)^2

(vi)

9/5 s2s^{2} + 6sv + 5v25v^{2} (Hint: 2 was taken out as a common factor in Example 7. Is it possible to do something similar in Exercises (v) and (vi) above?)

Answer

1/5(3s + 5v)^2

Explanation

Each expression can be compared with the identity (a + b)^2 = a2a^{2} + 2ab + b2b^{2}. For parts (v) and (vi), following the hint similar to Example 7, we take out a common factor to make the expression fit the perfect square identity, then factor accordingly.