Question 38 of 45advanced🔧 ApplyNumerical4 marks

A milkman sold two buffaloes for ₹80,000 each. On one of them, he made a profit of 5% and on the other a loss of 10%. Find his overall profit or loss.

Correct Answer

Given: First buffalo: SP = ₹80,000, Profit = 5% Second buffalo: SP = ₹80,000, Loss = 10%

Formula: For profit: CP = SP/(1 + profit%) For loss: CP = SP/(1 - loss%)

Calculation: First buffalo: CP₁ = 80,000/1.05 = 1,600,000/21 ≈\approx ₹76,190.48 Second buffalo: CP₂ = 80,000/0.90 = 800,000/9 ≈\approx ₹88,888.89 Total CP = 1,600,000/21 + 800,000/9 = 10,400,000/63 ≈\approx ₹1,65,079.37 Total SP = ₹1,60,000 Loss = 10,400,000/63 - 1,60,000 = 320,000/63 ≈\approx ₹5,079.37

Answer: Overall loss of ₹5,079.37

Exercise: Figure it Out (Section 3) | Q: 7 | (Chapter: Page 20)
For More Understanding

Explanation

The chapter shows how to find cost price when selling price and profit/loss percentage are given. For profit: CP = SP/(1 + profit%), For loss: CP = SP/(1 - loss%).

Solution Steps

  1. First buffalo: SP = ₹80,000, Profit = 5%

  2. CP₁ = 80,000/1.05 = 1,600,000/21 ≈\approx ₹76,190.48

  3. Second buffalo: SP = ₹80,000, Loss = 10%

  4. CP₂ = 80,000/0.90 = 800,000/9 ≈\approx ₹88,888.89

  5. Total CP = 1,600,000/21 + 800,000/9 = 10,400,000/63 ≈\approx ₹1,65,079.37

  6. Total SP = ₹1,60,000

  7. Loss = 10,400,000/63 - 1,60,000 = 320,000/63 ≈\approx ₹5,079.37

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