Question 20 of 27intermediate🔍 AnalyzeTrue / False2 marks

ab2+a2b+a2b2=ab(a+b+ab)ab^2 + a^2b + a^2b^2 = ab(a + b + ab)

Correct Answer

True. The factorization is correct. Factoring out abab from each term: ab2=ab⋅bab^2 = ab \cdot b, a2b=ab⋅aa^2b = ab \cdot a, and a2b2=ab⋅aba^2b^2 = ab \cdot ab. So ab2+a2b+a2b2=ab(b+a+ab)=ab(a+b+ab)ab^2 + a^2b + a^2b^2 = ab(b + a + ab) = ab(a + b + ab).

Exercise: Mind the Mistake, Mend the Mistake | Q: 12 | (Page Page 15)
For More Understanding

Explanation

The chapter discusses factoring by identifying common factors. Each term ab2ab^2, a2ba^2b, and a2b2a^2b^2 contains abab as a factor. Factoring out abab gives ab(b+a+ab)=ab(a+b+ab)ab(b + a + ab) = ab(a + b + ab).

Solution Steps

  1. Identify common factor in each term: abab

  2. ab2=ab⋅bab^2 = ab \cdot b

  3. a2b=ab⋅aa^2b = ab \cdot a

  4. a2b2=ab⋅aba^2b^2 = ab \cdot ab

  5. Factor: ab(b+a+ab)=ab(a+b+ab)ab(b + a + ab) = ab(a + b + ab)