Question 7 of 11intermediate🔧 ApplyNumerical3 marks

Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel.

(a)

What is the total capacitance of the combination?

Answer

9 pF

(b)

Determine the charge on each capacitor if the combination is connected to a 100 V supply.

Answer

Charge on 2 pF capacitor = 2×102 \times 10⁻¹⁰ C (200 pC), Charge on 3 pF capacitor = 3×103 \times 10⁻¹⁰ C (300 pC), Charge on 4 pF capacitor = 4×104 \times 10⁻¹⁰ C (400 pC)

Explanation

For parallel combination of capacitors, the total capacitance is the sum of individual capacitances. The potential difference across each capacitor is the same and equal to the supply voltage. The charge on each capacitor is calculated using Q = CV.