Question 6 of 11intermediate🔧 ApplyNumerical3 marks
Three capacitors each of capacitance 9 pF are connected in series.
(a)
What is the total capacitance of the combination?
Answer
3 pF
(b)
What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
Answer
40 V across each capacitor
Explanation
This question tests understanding of series combination of capacitors. From the context, for capacitors in series, the total capacitance C is given by 1/C = 1/C1 + 1/C2 + 1/C3. When capacitors are in series, the charge on each capacitor is the same, and the potential difference divides across them inversely proportional to their capacitance.