This question tests the relationship between peak and rms values in AC circuits. The rms (root mean square) value is related to the peak value by a factor of $\sqrt{2}$. For voltage: V = v_m/$\sqrt{2}$, and for current: I = i_m/$\sqrt{2}$. In part (a), we divide the peak voltage by $\sqrt{2}$ to get the rms voltage. In part (b), we multiply the rms current by $\sqrt{2}$ to get the peak current.