Consider the temperature (in Celsius) of 7 days of a week as 34, 34, 27, 28, 27, 34, 34. Identify the appropriate statistical technique to be used to calculate the following:
Find the average temperature.
To find the average temperature, we use Mean. Mean is the average of given numeric values. Calculation: Mean = (34 + 34 + 27 + 28 + 27 + 34 + 34) / 7 = 218 / 7 = 31.14°C (approx).
Find the temperature Range of that week.
To find the temperature Range, we use Range. Range is the difference between the maximum and minimum values. Maximum value = 34, Minimum value = 27. Range = 34 - 27 = 7°C.
Find the standard deviation temperature.
To find the standard deviation, we use Standard Deviation. It is the positive square root of the average of squared difference of each value from the mean. Mean = 31.14. Squared differences: (34-31.14)² + (34-31.14)² + (27-31.14)² + (28-31.14)² + (27-31.14)² + (34-31.14)² + (34-31.14)² = 8.18 + 8.18 + 17.14 + 9.86 + 17.14 + 8.18 + 8.18 = 76.86. Variance = 76.86/7 = 10.98. Standard Deviation = .98 = 3.31°C (approx).
Explanation
The question tests understanding of statistical techniques for data summarisation. Mean is used for finding average values, Range measures spread by finding difference between max and min values, and Standard Deviation measures dispersion of data from the mean. These are fundamental statistical techniques mentioned in the NCERT textbook for Class 12 Computer Science.