For part (i), the Cartesian product of two sets with 2 elements each must have 4 ordered pairs. The given statement only lists 2 pairs, missing $(m, m)$ and $(n, n)$. For part (ii), this is the standard definition of Cartesian product - when both sets are non-empty, their product contains all ordered pairs with first element from A and second from B. For part (iii), since $B \cap \phi = \phi$ (intersection with empty set is empty), and $A \times \phi = \phi$ (Cartesian product with empty set is empty), the statement is correct.