Question 48 of 70beginner🔧 ApplyShort Answer2 marks

In each of the Exercises 1 to 6, find the coordinates of the foci and the vertices, the eccentricity and the length of the latus rectum of the hyperbolas: x²/16 - y²/9 = 1

Correct Answer

For the hyperbola x²/16 - y²/9 = 1:

Coordinates of Foci: (±5, 0)

Coordinates of Vertices: (±4, 0)

Eccentricity: 5/4

Length of Latus Rectum: 9/2

Exercise: EXERCISE 10.4 | Q: 1 | (Page 27)
For More Understanding

Explanation

This question is from Exercise 10.4, Q1. The student needs to compare the given equation with the standard form x²/a² - y²/b² = 1. From the context, Example 14 shows the methodology: identify a² and b², then calculate c² = a² + b² (note: for hyperbola, c² = a² + b², unlike ellipse). The foci are at (±c, 0), vertices at (±a, 0), eccentricity e = c/a, and latus rectum = 2b²/a.

Solution Steps

  1. Step 1: Compare x²/16 - y²/9 = 1 with standard form x²/a² - y²/b² = 1. We get a² = 16, so a = 4; and b² = 9, so b = 3.

  2. Step 2: Calculate c² = a² + b² = 16 + 9 = 25, so c = 5.

  3. Step 3: Foci are at (±c, 0) = (±5, 0). Vertices are at (±a, 0) = (±4, 0).

  4. Step 4: Eccentricity e = c/a = 5/4.

  5. Step 5: Length of latus rectum = 2b²/a = 2(9)/4 = 9/2.