Question 30 of 34intermediate🔧 ApplyMCQ1 mark

In the organic compound CH₂ = CH – CH₂ – CH₂ – C ≡ CH, the pair of hydridised orbitals involved in the formation of: C₂ – C₃ bond is:

Exercise: EXERCISES | Q: 8.36
For More Understanding

Explanation

Option (C) is correct. In the given compound CH2=CH−CH2−CH2−C≡CH\text{CH}_2 = \text{CH} - \text{CH}_2 - \text{CH}_2 - \text{C} \equiv \text{CH}, the carbon atoms are numbered from left to right as C1 to C6. C2 is part of a carbon-carbon double bond (C1=C2\text{C}_1=\text{C}_2), making it sp2sp^2 hybridised. C3 is connected by single bonds only, making it sp3sp^3 hybridised. Therefore, the C2−C3\text{C}_2 - \text{C}_3 bond is formed by the overlap of an sp2sp^2 hybrid orbital of C2 and an sp3sp^3 hybrid orbital of C3.

Solution Steps

  1. Step 1: Identify the hybridisation of C2. Since C2 is part of a carbon-carbon double bond (CH2=CH−\text{CH}_2=\text{CH}-), it is sp2sp^2 hybridised.

  2. Step 2: Identify the hybridisation of C3. Since C3 is bonded via single bonds (−CH2−-\text{CH}_2-), it is sp3sp^3 hybridised.

  3. Step 3: Conclude the orbitals forming the C2−C3\text{C}_2 - \text{C}_3 bond. The bond is formed by the overlap of sp2sp^2 and sp3sp^3 hybrid orbitals, which corresponds to option (C).

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