Question 28 of 34intermediate🔧 ApplyNumerical3 marks

0.3780 g of an organic chloro compound gave 0.5740 g of silver chloride in Carius estimation. Calculate the percentage of chlorine present in the compound.

Correct Answer

37.57%

Exercise: EXERCISES | Q: 8.34
For More Understanding

Explanation

In the Carius method for halogen estimation, the organic compound is heated with fuming nitric acid and silver nitrate. The halogen forms the corresponding silver halide (AgX), which is weighed. The percentage of halogen is calculated using the formula: Percentage of halogen = (atomic mass of X × mass of AgX × 100) / (molecular mass of AgX × mass of organic compound).

Solution Steps

  1. Step 1: Identify the given values. Mass of organic compound (mm) = 0.3780 g, Mass of AgCl formed (m1m_1) = 0.5740 g.

  2. Step 2: Determine the molar masses. Atomic mass of Cl = 35.5 g/mol, Molar mass of AgCl = 108 + 35.5 = 143.5 g/mol.

  3. Step 3: Apply the formula for percentage of halogen. Percentage of chlorine = atomic mass of Cl×m1×100molar mass of AgCl×m\frac{\text{atomic mass of Cl} \times m_1 \times 100}{\text{molar mass of AgCl} \times m}

  4. Step 4: Substitute the values. Percentage of chlorine = 35.5×0.5740×100143.5×0.3780=2037.754.243=37.57%\frac{35.5 \times 0.5740 \times 100}{143.5 \times 0.3780} = \frac{2037.7}{54.243} = 37.57\%

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