Write structures of different isomeric alkyl groups corresponding to the molecular formula C₅H₁₁. Write IUPAC names of alcohols obtained by attachment of –OH groups at different carbons of the chain.
The eight isomeric alkyl groups for the molecular formula and their corresponding alcohols are:
(i) gives (Pentan-1-ol) (ii) gives (Pentan-2-ol) (iii) gives (Pentan-3-ol) (iv) gives (3-Methylbutan-1-ol) (v) gives (2-Methylbutan-1-ol) (vi) gives (2-Methylbutan-2-ol) (vii) gives (2,2-Dimethylpropan-1-ol) (viii) gives (3-Methylbutan-2-ol)
Explanation
Alkyl groups are derived from alkanes by the removal of one hydrogen atom, having the general formula . For the group, there are eight possible structural isomers. By attaching a hydroxyl () group to the free valence of each isomeric alkyl group, we obtain the corresponding isomeric alcohols, which are named according to IUPAC nomenclature rules.
Solution Steps
Step 1: Identify the straight-chain alkyl group and attach to get Pentan-1-ol.
Step 2: Identify the branched-chain alkyl groups by varying the position of the methyl substituent and the free valence.
Step 3: Attach the group to the free valence of each of the eight isomeric groups and write their respective IUPAC names: Pentan-2-ol, Pentan-3-ol, 3-Methylbutan-1-ol, 2-Methylbutan-1-ol, 2-Methylbutan-2-ol, 2,2-Dimethylpropan-1-ol, and 3-Methylbutan-2-ol.