Question 1 of 32intermediate🔧 ApplyShort Answer2 marks

Write structures of different chain isomers of alkanes corresponding to the molecular formula C₆H₁₄. Also write their IUPAC names.

Correct Answer

The molecular formula C6H14C_6H_{14} exhibits five chain isomers. Their structures and IUPAC names are:

(i) CH3−CH2−CH2−CH2−CH2−CH3CH_3 - CH_2 - CH_2 - CH_2 - CH_2 - CH_3 (n-Hexane) (ii) CH3−CH(CH3)−CH2−CH2−CH3CH_3 - CH(CH_3) - CH_2 - CH_2 - CH_3 (2-Methylpentane) (iii) CH3−CH2−CH(CH3)−CH2−CH3CH_3 - CH_2 - CH(CH_3) - CH_2 - CH_3 (3-Methylpentane)

The remaining two isomers are: (iv) CH3−CH(CH3)−CH(CH3)−CH3CH_3 - CH(CH_3) - CH(CH_3) - CH_3 (2,3-Dimethylbutane) (v) CH3−C(CH3)2−CH2−CH3CH_3 - C(CH_3)_2 - CH_2 - CH_3 (2,2-Dimethylbutane)

Exercise: Problem 9.1 | Q: 9.1 | (Page Page 3)
For More Understanding

Explanation

The question asks for the chain isomers of the alkane with formula C6H14. According to the provided context, there are five possible isomers. These are formed by varying the length of the main carbon chain and branching methyl groups, resulting in n-hexane, 2-methylpentane, 3-methylpentane, 2,3-dimethylbutane, and 2,2-dimethylbutane.

Solution Steps

  1. Step 1: Identify the molecular formula C6H14C_6H_{14}, which corresponds to an alkane.

  2. Step 2: Draw the straight-chain structure and name it n-Hexane.

  3. Step 3: Create branched structures by moving methyl groups along the chain to form 2-Methylpentane, 3-Methylpentane, 2,3-Dimethylbutane, and 2,2-Dimethylbutane.

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