At 450K, $K_p = 2.0 \times 10^{10}$/bar for the given reaction at equ… — Chemistry · Equilibrium

Question 2 of 71intermediate🔧 ApplyNumerical2 marks

At 450K, $K_p = 2.0 \times 10^{10}$ /bar for the given reaction at equilibrium. $2SO_2 (g) + O_2 (g) \rightleftharpoons 2SO_3 (g)$ What is $K_c$ at this temperature?

Correct Answer

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Exercise: EXERCISES | Q: 6.10 | (Chapter: 42)