Question 47 of 69beginner🔧 ApplyNumerical2 marks

Assuming complete dissociation, calculate the pH of the following solutions: (a) 0.003 M HCl (b) 0.005 M NaOH (c) 0.002 M HBr (d) 0.002 M KOH

(a)
Answer

2.52

(b)
Answer

11.70

(c)
Answer

2.70

(d)
Answer

11.30

Explanation

For strong acids and bases, which dissociate completely, the concentration of H+\text{H}^+ or OH−\text{OH}^- is equal to the initial concentration of the acid or base. The pH is calculated using pH=−log⁡[H+]\text{pH} = -\log [\text{H}^+]. For bases, [H+][\text{H}^+] is found using the water dissociation constant Kw=[H+][OH−]=10−14K_w = [\text{H}^+][\text{OH}^-] = 10^{-14}.

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