Question 38 of 48intermediate🔧 ApplyShort Answer3 marks

Assign the position of the element having outer electronic configuration (i) ns² np⁴ for n=3 (ii) (n-1)d² ns² for n=4, and (iii) (n-2)f⁷ (n-1)d¹ ns² for n=6, in the periodic table.

(i)
Answer

3rd period, Group 16

(ii)
Answer

4th period, Group 4

(iii)
Answer

6th period, Group 3

Explanation

The period of an element is determined by the value of the principal quantum number nn of the outermost shell. The group is determined by the valence shell electronic configuration. For (i), n=3n=3 gives the 3rd period, and ns2np4ns^2 np^4 gives Group 16. For (ii), n=4n=4 gives the 4th period, and (n−1)d2ns2(n-1)d^2 ns^2 gives Group 4 of the d-block. For (iii), n=6n=6 gives the 6th period, and (n−2)f7(n−1)d1ns2(n-2)f^7 (n-1)d^1 ns^2 gives Group 3 of the f-block.