Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.
| Number of heartbeats per minute | 65 - 68 | 68 - 71 | 71 - 74 | 74 - 77 | 77 - 80 | 80 - 83 | 83 - 86 |
|---|---|---|---|---|---|---|---|
| Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
To find the mean heartbeats per minute, we use the Direct Method by finding the class marks for each interval.
Step 1: Calculate the class mark () for each class interval using the formula .
Step 2: Compute the product of frequency and class mark () for each class.
Calculation Table:
| Class Interval | Number of women () | Class Mark () | |
|---|---|---|---|
| 65 - 68 | 2 | 66.5 | 133.0 |
| 68 - 71 | 4 | 69.5 | 278.0 |
| 71 - 74 | 3 | 72.5 | 217.5 |
| 74 - 77 | 8 | 75.5 | 604.0 |
| 77 - 80 | 7 | 78.5 | 549.5 |
| 80 - 83 | 4 | 81.5 | 326.0 |
| 83 - 86 | 2 | 84.5 | 169.0 |
| Total |
Step 3: Apply the mean formula:
The mean heartbeats per minute for these women is 75.9.
Explanation
The solution follows the method demonstrated in Example 2 of the provided context, where the mean is calculated using class marks (). The Direct Method is suitable here because the class sizes are uniform (3) and the frequencies are manageable. We determine the class mark for each interval, multiply it by the frequency, sum these products, and divide by the total number of women to find the mean.
Solution Steps
Step 1: Identify class intervals and frequencies. Calculate class marks () as the average of upper and lower limits (e.g., for 65-68, ).
Step 2: Multiply the frequency () by the corresponding class mark () to get values: 133, 278, 217.5, 604, 549.5, 326, 169.
Step 3: Sum the frequencies to get and sum the products to get .
Step 4: Calculate Mean .