Consider the following distribution of daily wages of 50 workers of a factory.
| Daily wages (in ₹) | 500 - 520 | 520-540 | 540 - 560 | 560 - 580 | 580 - 600 |
|---|---|---|---|---|---|
| Number of workers | 12 | 14 | 8 | 6 | 10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
To find the mean daily wages, we will use the Direct Method. This method is appropriate here as the class sizes are uniform and the values of the class marks () are manageable integers.
First, we calculate the class mark () for each class interval using the formula . Then, we compute the product for each class.
Table Calculation:
| Daily wages (in ₹) | Number of workers () | Class mark () | |
|---|---|---|---|
| 500 - 520 | 12 | 510 | 6120 |
| 520 - 540 | 14 | 530 | 7420 |
| 540 - 560 | 8 | 550 | 4400 |
| 560 - 580 | 6 | 570 | 3420 |
| 580 - 600 | 10 | 590 | 5900 |
| Total |
Mean Calculation: Using the formula from the Direct Method:
Substituting the values:
Thus, the mean daily wages of the workers is ₹ 545.20.
Explanation
The solution follows the Direct Method for finding the mean of grouped data, as illustrated in Table 13.3 of the provided context. This method is chosen because the class marks () are small integers, making the calculation of straightforward without needing the step-deviation method. The class mark is calculated as the average of the upper and lower limits for each class interval. The sum of the frequencies () is 50, and the sum of the products of frequency and class mark () is 27260. Dividing the total wages by the total number of workers yields the mean.
Solution Steps
Step 1: Identify the method. Since the class marks are small integers, the Direct Method is appropriate.
Step 2: Calculate class marks () for each wage interval (e.g., for 500-520, ).
Step 3: Multiply the number of workers () by the class mark () for each row to get .
Step 4: Sum the values to get and sum the frequencies to get .
Step 5: Apply the mean formula .