Question 7 of 11intermediate🔧 ApplyNumerical2 marks

Find the nature of the roots of the following quadratic equations. If the real roots exist, find them:

(i)

2x2−3x+5=02x^2 - 3x + 5 = 0

Answer

No real roots exist.

(ii)

3x2−43x+4=03x^2 - 4\sqrt{3}x + 4 = 0

Answer

Two equal real roots exist: x = 23\sqrt{3}/3

(iii)

2x2−6x+3=02x^2 - 6x + 3 = 0

Answer

Two distinct real roots exist: x = (3 + 3\sqrt{3})/2 and x = (3 - 3\sqrt{3})/2

Explanation

This question tests the concept of discriminant and nature of roots from the chapter on Quadratic Equations. The discriminant (b² - 4ac) determines the nature of roots: positive means two distinct real roots, zero means two equal real roots, and negative means no real roots.