This question is from Exercise 13 of the NCERT textbook. When a die is thrown once, there are 6 equally likely outcomes: 1, 2, 3, 4, 5, 6. For each part, we identify favourable outcomes and divide by total outcomes. Following the method shown in Example 3 of the textbook, probability P(E) = (number of favourable outcomes)/(total number of possible outcomes).