Question 17 of 18intermediate🔧 ApplyShort Answer4 marks

Choose the correct option. Justify your choice.

(i)

9sec⁡2A−9tan⁡2A=9 \sec^2 A - 9 \tan^2 A =

Answer

B

(ii)

(1+tan⁡θ+sec⁡θ)(1+cot⁡θ−cosec⁡θ)=(1 + \tan \theta + \sec \theta) (1 + \cot \theta - \cosec \theta) =

Answer

C

(iii)

(sec⁡A+tan⁡A)(1−sin⁡A)=(\sec A + \tan A) (1 - \sin A) =

Answer

D

(iv)

1+tan⁡2A1+cot⁡2A=\frac{1 + \tan^2 A}{1 + \cot^2 A} =

Answer

D

Explanation

These questions are from Exercise 8.3, Question 3 of the NCERT textbook. Each requires application of fundamental trigonometric identities.

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