If (1, 2), (4, y), (x, 6) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.
x = 6 and y = 3
Explanation
This question is similar to Example 10 in the textbook. The key property used is that the diagonals of a parallelogram bisect each other. When vertices are given 'in order' as A(1, 2), B(4, y), C(x, 6), D(3, 5), the diagonals are AC and BD. The midpoint of diagonal AC must equal the midpoint of diagonal BD. This gives us two equations which can be solved for x and y.
Solution Steps
Step 1: Let the vertices be A(1, 2), B(4, y), C(x, 6), D(3, 5) taken in order.
Step 2: Since diagonals of a parallelogram bisect each other, the midpoint of AC = midpoint of BD.
Step 3: Midpoint of AC = ((1 + x)/2, (2 + 6)/2) = ((1 + x)/2, 4)
Step 4: Midpoint of BD = ((4 + 3)/2, (y + 5)/2) = (7/2, (y + 5)/2)
Step 5: Equating the coordinates: (1 + x)/2 = 7/2 and 4 = (y + 5)/2
Step 6: From first equation: 1 + x = 7, so x = 6
Step 7: From second equation: 8 = y + 5, so y = 3