Question 6 of 17advanced🔧 ApplyNumerical5 marks

A coconut of mass 1.5 kg falls from the top of a coconut tree onto the wet sand on a beach. The height of the tree is 10 m. On impact, the coconut comes to rest by making a depression in the sand.

(i)

Calculate the velocity of the coconut just before it hits the sand.

Answer

Given: Mass, m = 1.5 kg; Height, h = 10 m; Initial velocity, u = 0; g = 10 m s⁻².

Formula: Using the equation of motion, v² = u² + 2gh

Calculation: v² = 0 + 2×102 \times 10 × 10 = 200

Result: v = 200\sqrt{200} = 102\sqrt{2} m/s \approx 14.14 m/s

(ii)

Assume that the average resistive force of sand is 3000 N and all of the coconut's energy is used to create the depression in the sand. Calculate the depth of the depression the coconut makes in the sand. Assume g = 10 m s⁻².

Answer

Given: Average resistive force, F = 3000 N

Energy of coconut: The total energy of the coconut just before hitting the sand is its potential energy at the top, E = mgh = 1.5×101.5 \times 10 × 10 = 150 J.

Formula: Work done by the resistive force = Energy of the coconut. So, F × d = mgh

Calculation: 3000 × d = 150

Result: d = 150 / 3000 = 0.05 m

Explanation

Part (i) uses the kinematic equation v² = u² + 2gh to find the final velocity of a freely falling object. Part (ii) applies the work-energy theorem, where the work done by the resistive force of the sand equals the initial potential energy of the coconut, as all its energy is used to create the depression.