Metal M, with two electrons in its valence shell (M shell), reacts with oxygen to form a compound that is slightly soluble in water. Predict its: (i) formula (ii) type of bond (iii) electrical conductivity of its aqueous solution.
MO
Ionic bond
Low electrical conductivity (due to slight solubility in water)
Explanation
Metal M has two electrons in its valence shell (M shell), so it loses two electrons to form M²⁺ ion. Oxygen has six electrons in its valence shell and needs two electrons to complete its octet, forming O²⁻ ion. The compound formed is MO with an ionic bond (transfer of electrons from metal to non-metal). Since the compound is only slightly soluble in water, fewer ions are available in the aqueous solution, resulting in low electrical conductivity. This aligns with the textbook context that ionic compounds conduct electricity when dissolved in water, but slight solubility limits the number of free ions.