Question 6 of 43intermediate🔧 ApplyNumerical3 marks

Carbon monoxide (CO) contains carbon and oxygen in the mass ratio of 3:4. How much oxygen will combine with 9 g of carbon to form carbon monoxide?

Correct Answer

According to the Law of Constant Proportions, elements in a chemical compound combine in a fixed ratio by mass. For carbon monoxide (CO), the given mass ratio of carbon to oxygen is 3:4.

To find the mass of oxygen that combines with 9 g of carbon, we set up the proportion based on the fixed ratio: Mass of Carbon / Mass of Oxygen = 3 / 4

Substituting the given mass of carbon: 9 g / Mass of Oxygen = 3 / 4

Solving for the Mass of Oxygen: Mass of Oxygen = (4 / 3) × 9 g = 12 g

Therefore, 12 g of oxygen will combine with 9 g of carbon to form carbon monoxide.

Exercise: Pause and Ponder | Q: 4 | (Page 6)
For More Understanding

Explanation

The question applies the Law of Constant Proportions, which states that elements in a compound combine in a fixed ratio by mass irrespective of its source. Since the mass ratio of carbon to oxygen in CO is given as 3:4, we can use a simple proportion to find the required mass of oxygen for 9 g of carbon.

Solution Steps

  1. Step 1: Identify the fixed mass ratio of Carbon to Oxygen in CO, which is 3:4.

  2. Step 2: Set up the proportion equation: Mass of Carbon / Mass of Oxygen = 3 / 4.

  3. Step 3: Substitute the given mass of carbon (9 g) into the equation: 9 / Mass of Oxygen = 3 / 4.

  4. Step 4: Solve for Mass of Oxygen: Mass of Oxygen = (4 / 3) × 9 = 12 g.

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