Question 12 of 51beginner🔧 ApplyNumerical2 marks

Which term of the sequence tn=5n−3t_n = 5n - 3 for n≥1n \geq 1 is 607?

Correct Answer

122nd term

Exercise: Exercise Set 8.1 | Q: 4 | (Page 6)
For More Understanding

Explanation

To find which term of the sequence equals 607, the formula for the nth term is equated to 607 and solved for n. As established in the textbook context, if the resulting value of n is a natural number, the given number is a valid term of the sequence.

Solution Steps

  1. Step 1: Equate the nthn^{th} term to 607: 5n−3=6075n - 3 = 607

  2. Step 2: Solve for nn: 5n=607+35n = 607 + 3, which gives 5n=6105n = 610 and n=122n = 122

  3. Step 3: Conclude the term number: Since 122 is a natural number, 607 is the 122nd term of the sequence.