Question 9 of 51beginner🔧 ApplyNumerical5 marks

Find the first five terms of the sequence in which the nthn^{th} term is given by (i) tn=3n−4t_n = 3n - 4, (ii) tn=2−5nt_n = 2 - 5n, and (iii) tn=n2−2n+3t_n = n^2 - 2n + 3 for n≥1n \geq 1.

(i)
Answer

-1, 2, 5, 8, 11

(ii)
Answer

-3, -8, -13, -18, -23

(iii)
Answer

2, 3, 6, 11, 18

Explanation

To find the first five terms of a sequence when the nthn^{th} term is provided, we must successively substitute the values of nn as 1, 2, 3, 4, and 5 into the given formula. The textbook context illustrates this direct method of computing terms by inserting the values of nn and calculating the result step-by-step.

For Part (i), the formula is linear. We substitute n=1n=1 to n=5n=5 into tn=3n−4t_n = 3n - 4 to yield the terms -1, 2, 5, 8, and 11. This creates a sequence where each term increases by a constant difference.

For Part (ii), we use another linear formula, tn=2−5nt_n = 2 - 5n. Substituting the first five natural numbers gives the sequence of terms -3, -8, -13, -18, and -23. Here, the terms decrease as nn increases due to the negative coefficient of nn.

For Part (iii), the formula is quadratic: tn=n2−2n+3t_n = n^2 - 2n + 3. By substituting n=1n=1, we get 1−2+3=21 - 2 + 3 = 2. Similarly, substituting n=2,3,4,n=2, 3, 4, and 55 yields the values 3, 6, 11, and 18 respectively. This step-by-step substitution ensures we accurately compute each term based on its position.