Question 34 of 49intermediate🔍 AnalyzeShort Answer2 marks

Differentiate between the graphs of the equations y=3x+1y = 3x + 1, and y=−3x+1y = -3x + 1.

Correct Answer

Both equations are in the form y=ax+by = ax + b. Since both have the same value for bb (which is 11), they share the same y-intercept. This means both lines cut the y-axis at the same point, (0,1)(0, 1).

However, they differ in their slope because the value of aa is different. The equation y=3x+1y = 3x + 1 has a positive slope (a=3a = 3), causing the line to rise from left to right. In contrast, y=−3x+1y = -3x + 1 has a negative slope (a=−3a = -3), causing the line to fall from left to right. Changing the value of aa while keeping bb fixed changes the slope of the line.

Exercise: Think and Reflect | Q: 1 | (Page 18)
For More Understanding

Explanation

The textbook context establishes that in the linear equation y=ax+by = ax + b, aa represents the slope and bb represents the y-intercept. For both y=3x+1y = 3x + 1 and y=−3x+1y = -3x + 1, the value of bb is 11, meaning they intersect the y-axis at the same point.

The difference arises from the value of aa (33 versus −3-3). The context notes that changing aa while keeping bb fixed changes the slope, which alters the steepness and direction (positive vs. negative) of the line.