Show that rectangle is the only parallelogram that can be inscribed in a circle.
Let ABCD be a parallelogram inscribed in a circle. Since all its vertices lie on the circle, ABCD is a cyclic quadrilateral.
By Theorem 11, the sum of two opposite angles of a cyclic quadrilateral is . Therefore,
and
In any parallelogram, opposite angles are equal. So,
and
Substituting into the first equation, we get
which means
Thus,
This implies . Similarly, .
Since all angles of the parallelogram are , it must be a rectangle. Conversely, a rectangle can be inscribed in a circle as its opposite angles sum to (by Theorem 12). Hence, a rectangle is the only parallelogram that can be inscribed in a circle.
Explanation
The proof logically combines the angle properties of a cyclic quadrilateral and a parallelogram. Theorem 11 establishes that opposite angles of a cyclic quadrilateral are supplementary (sum to ). A fundamental property of parallelograms is that their opposite angles are equal. The only way an angle can be equal to another angle while simultaneously summing to with it is if both angles are . Thus, all angles must be right angles, making the parallelogram a rectangle. The converse is verified using Theorem 12, confirming that rectangles can indeed be inscribed in a circle.
Solution Steps
Step 1: Assume a parallelogram ABCD is inscribed in a circle, making it a cyclic quadrilateral.
Step 2: Apply Theorem 11: Opposite angles of a cyclic quadrilateral sum to ().
Step 3: Apply parallelogram property: Opposite angles are equal ().
Step 4: Combine the equations to get , yielding and . Similarly, .
Step 5: Conclude that a parallelogram with all angles is a rectangle, and confirm the converse using Theorem 12.