Question 45 of 45advanced🔍 AnalyzeNumerical4 marks

In a room of 100 people, 99% are left-handed. How many left-handed people have to leave the room to bring that percentage down to 98%?

Correct Answer

Given: Total people = 100 Left-handed people = 99% of 100 = 99 Right-handed people = 1

Let: x = number of left-handed people who leave

Remaining: Left-handed = 99 - x Total people = 100 - x

Equation: (99 - x) / (100 - x) = 0.98

Solution: 99 - x = 0.98(100 - x) 99 - x = 98 - 0.98x 1 = 0.02x x = 50

Answer: ∴ 50 left-handed people must leave.

Exercise: Figure it Out (Section 5) | Q: 14 | (Page Page 30)
For More Understanding

Explanation

This is a classic percentage problem where both numerator and denominator change. The key insight is that the number of right-handed people (1) stays constant.

Solution Steps

  1. Initial: 99 left-handed, 1 right-handed

  2. Let x left-handed people leave

  3. Remaining: (99-x) left-handed, (100-x) total

  4. (99-x)/(100-x) = 0.98

  5. 99 - x = 98 - 0.98x

  6. 1 = 0.02x

  7. x = 50

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