Question 34 of 45intermediate🔧 ApplyNumerical3 marks

In a laboratory, the number of bacteria in a certain experiment increases at the rate of 2.5% per hour. Find the number of bacteria at the end of 2 hours if the initial count is 5,06,000.

Correct Answer

Given: Initial count = 5,06,000 Growth rate = 2.5% per hour

Calculation: Number of bacteria after 2 hours = 5,06,000 × (1.025)² = 5,06,000×1.050625000 \times 1.050625 = 5,31,616

Answer: 5,31,616 bacteria (approximately)

Exercise: Figure it Out (Section 4) | Q: 9 | (Page Page 24)
For More Understanding

Explanation

The chapter applies compound growth formula to bacterial growth. The bacteria count grows exponentially at 2.5% per hour.

Solution Steps

  1. Initial count = 5,06,000

  2. Growth rate = 2.5% per hour

  3. After 2 hours = 5,06,000 × (1.025)²

  4. = 5,06,000×1.050625000 \times 1.050625

  5. = 5,31,616 bacteria

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