Question 6 of 28intermediate🔧 ApplyNumerical4 marks

If 122=14412^2 = 144 what is (i) (1.2)2(1.2)^2 (ii) (0.12)2(0.12)^2 (iii) (0.012)2(0.012)^2 (iv) 1202120^2

(i)
Answer

1.44

(ii)
Answer

0.0144

(iii)
Answer

0.000144

(iv)
Answer

14400

Explanation

(i) 1.2=12÷101.2 = 12 \div 10, so (1.2)2=144÷100=1.44(1.2)^2 = 144 \div 100 = 1.44 (ii) 0.12=12÷1000.12 = 12 \div 100, so (0.12)2=144÷10000=0.0144(0.12)^2 = 144 \div 10000 = 0.0144 (iii) 0.012=12÷10000.012 = 12 \div 1000, so (0.012)2=144÷1000000=0.000144(0.012)^2 = 144 \div 1000000 = 0.000144 (iv) 120=12×10120 = 12 \times 10, so 1202=144×100=14400120^2 = 144 \times 100 = 14400

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