Question 1 of 31beginner🔧 ApplyNumerical2 marks

The sum of four consecutive numbers is 34. What are these numbers?

Correct Answer

Let: The four consecutive numbers be n, n+1, n+2, n+3

Sum: n + (n+1) + (n+2) + (n+3) = 4n + 6 = 34

Solving: 4n = 28 n = 7

Answer: The four consecutive numbers are 7, 8, 9, and 10.

Exercise: Figure it Out (Section 1) | Q: 1 | (Page Page 11)
For More Understanding

Explanation

Let the four consecutive numbers be n, n+1, n+2, and n+3. Their sum is n + (n+1) + (n+2) + (n+3) = 4n + 6 = 34. Solving: 4n = 28, so n = 7. Therefore, the numbers are 7, 8, 9, and 10.

Solution Steps

  1. Let the first number be n

  2. Four consecutive numbers: n, n+1, n+2, n+3

  3. Sum = n + (n+1) + (n+2) + (n+3) = 4n + 6

  4. Set 4n + 6 = 34

  5. 4n = 28, n = 7

  6. Numbers are 7, 8, 9, 10

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