Question 21 of 21intermediate🔧 ApplyNumerical4 marks

The ancient Indians likely used base 10 for the Hindu number system because humans have 10 fingers, and so we can use our fingers to count. But what if we had only 8 fingers? How would we be writing numbers then? What would the Hindu numerals look like if we were using base 8 instead? Base 5? Try writing the base-10 Hindu numeral 25 as base-8 and base-5 Hindu numerals, respectively. Can you write it in base-2?

Correct Answer

Context: If humans had 8 fingers, we would likely use base-8 (octal) with digits 0-7.

Given: Base-10 numeral 25

Base-8 (Octal) Conversion: 25 = 3×83 \times 8 + 1 = 31 (octal)

Base-5 Conversion: 25 = 1×251 \times 25 + 0×50 \times 5 + 0×10 \times 1 = 100 (base-5)

Base-2 (Binary) Conversion: 25 = 1×161 \times 16 + 1×81 \times 8 + 0×40 \times 4 + 0×20 \times 2 + 1×11 \times 1 = 11001 (binary)

Verification: 31 (base-8) = 3×83 \times 8 + 1 = 25 ✓ 100 (base-5) = 1×251 \times 25 + 0×50 \times 5 + 0×10 \times 1 = 25 ✓ 11001 (base-2) = 16 + 8 + 0 + 0 + 1 = 25 ✓

Answer:

  • 25 in base-8 = 31
  • 25 in base-5 = 100
  • 25 in base-2 = 11001

Note: In base-8, we would need only 8 digits (0-7). In base-5, we would need only 5 digits (0-4). In base-2 (binary), we need only 2 digits (0 and 1), which is why computers use binary.

Exercise: Figure it Out (Section 10) | Q: 4 | (Page Page 33)
For More Understanding

Explanation

The chapter explains that base-n systems use digits 0 to (n-1) and positions representing powers of n. The conversion process involves expressing a number as sums of powers of the base. For base-8: 25 = 3×83 \times 8¹ + 1×81 \times 8⁰ = 31. For base-5: 25 = 1×51 \times 5² + 0×50 \times 5¹ + 0×50 \times 5⁰ = 100. For base-2: 25 = 1×161 \times 16 + 1×81 \times 8 + 0×40 \times 4 + 0×20 \times 2 + 1×11 \times 1 = 11001. The chapter notes that ancient Indians likely chose base-10 because humans have 10 fingers for counting.

Solution Steps

  1. Step 1: For base-8 conversion of 25: 25 ÷ 8 = 3 remainder 1, so 25 = 31 in base-8

  2. Step 2: For base-5 conversion of 25: 25 ÷ 25 = 1 remainder 0, 0 ÷ 5 = 0 remainder 0, so 25 = 100 in base-5

  3. Step 3: For base-2 conversion of 25: 25 = 16 + 8 + 1 = 2⁴ + 2³ + 2⁰, so 25 = 11001 in binary

  4. Step 4: Verify: 31 (base-8) = 3×83 \times 8 + 1 = 25 ✓

  5. Step 5: Verify: 100 (base-5) = 1×251 \times 25 + 0×50 \times 5 + 0×10 \times 1 = 25 ✓

  6. Step 6: Verify: 11001 (base-2) = 16 + 8 + 0 + 0 + 1 = 25 ✓