Question 8 of 19intermediate🔧 ApplyNumerical5 marks

Given 4k+1=134k + 1 = 13, find the values of: (a) 8k+28k + 2 (b) 4k4k (c) kk (d) 4k−14k - 1 (e) −k−2-k - 2

(a)
Answer

8k+2=268k + 2 = 26

(b)
Answer

4k=124k = 12

(c)
Answer

k=3k = 3

(d)
Answer

4k−1=114k - 1 = 11

(e)
Answer

−k−2=−5-k - 2 = -5

Explanation

(a) From 4k+1=134k + 1 = 13, we get 4k=124k = 12, so k=3k = 3. Substituting: 8(3)+2=24+2=268(3) + 2 = 24 + 2 = 26. (b) From the equation 4k+1=134k + 1 = 13, subtracting 1 from both sides gives 4k=124k = 12. (c) From 4k=124k = 12, dividing by 4 gives k=3k = 3. (d) Substituting k=3k = 3: 4(3)−1=12−1=114(3) - 1 = 12 - 1 = 11. (e) Substituting k=3k = 3: −(3)−2=−3−2=−5-(3) - 2 = -3 - 2 = -5.