Question 6 of 29intermediate💡 UnderstandNumerical3 marks

The price of 1 kg of oranges is ₹56.50. What is the price of 2.250 kg of oranges? Can we write 56.50 as 56.5 and 2.250 as 2.25 and multiply? Will we get the same product? Why?

Correct Answer

Given: Price of 1 kg oranges = ₹56.50, Quantity = 2.250 kg Formula: Total Price = Price per kg × Quantity Substitution: Total Price = 56.50×2.25056.50 \times 2.250 Calculation: 56.50×2.25056.50 \times 2.250 = 5650/100×2250100 \times 2250/1000 = 12712500 / 100000 = 127.125

Answer: The price of 2.250 kg of oranges is ₹127.125.

Concept Check: Can we write 56.50 as 56.5 and 2.250 as 2.25? Answer: Yes, we can write 56.50 as 56.5 and 2.250 as 2.25 and multiply. Reason: We will get the same product because trailing zeros after the decimal point do not change the value of the number.

Verification: 56.5×2.2556.5 \times 2.25 = 565/10×22510 \times 225/100 = 127125 / 1000 = 127.125 ∴ 56.50×2.25056.50 \times 2.250 = 56.5×2.2556.5 \times 2.25 = 127.125

Exercise: Figure it Out (Section 1) | Q: 6 | (Page Page 7)
For More Understanding

Explanation

56.50 and 56.5 represent the same value, as do 2.250 and 2.25. The trailing zeros after the decimal point do not affect the value. So 56.50×2.25056.50 \times 2.250 = 56.5×2.2556.5 \times 2.25 = 127.125.

Solution Steps

  1. Identify given values: Price = ₹56.50, Quantity = 2.250 kg.

  2. Set up multiplication: Price = 56.50×2.25056.50 \times 2.250.

  3. Convert decimals to fractions: 5650/100×2250100 \times 2250/1000.

  4. Multiply numerators and denominators: 12712500 / 100000.

  5. Divide to find product: 127.125.

  6. Verify using simplified decimals: 56.5×2.2556.5 \times 2.25.

  7. Convert to fractions: 565/10×22510 \times 225/100.

  8. Calculate product: 127125 / 1000 = 127.125.

  9. Conclude that trailing zeros do not affect the value.

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