Question 10 of 20intermediate🔧 ApplyNumerical3 marks

Tsewang plants four saplings in a row in his garden. The distance between two saplings is 34\frac{3}{4} m. Find the distance between the first and last sapling. [Hint: Draw a rough diagram with four saplings with distance between two saplings as 34\frac{3}{4} m]

Correct Answer

Given: 4 saplings in a row. Distance between two saplings = 34\frac{3}{4} m.

Logic: With 4 saplings in a row, there are 3 gaps between the first and last sapling.

Calculation: Total distance = 3×343 \times \frac{3}{4} Total distance = 94\frac{9}{4} m Total distance = 2142\frac{1}{4} m

Answer: The distance between the first and last sapling is 2142\frac{1}{4} metres.

Exercise: Figure it Out (Section 3) | Q: 4 | (Page Page 12)
For More Understanding

Explanation

The chapter explains multiplication of fractions. With 4 saplings in a row, there are 3 gaps between them. Each gap is 34\frac{3}{4} m. Total distance = 3×34=94=2143 \times \frac{3}{4} = \frac{9}{4} = 2\frac{1}{4} m.

Solution Steps

  1. Step 1: Four saplings have 3 gaps between first and last

  2. Step 2: Distance = 3×34=943 \times \frac{3}{4} = \frac{9}{4} m

  3. Step 3: Convert to mixed fraction: 94=214\frac{9}{4} = 2\frac{1}{4} m

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