Question 12 of 20intermediate🔧 ApplyNumerical10 marks

Evaluate the following: 3÷793 \div \frac{7}{9}, 144÷2\frac{14}{4} \div 2, 23÷23\frac{2}{3} \div \frac{2}{3}, 146÷73\frac{14}{6} \div \frac{7}{3}, 43÷34\frac{4}{3} \div \frac{3}{4}, 74÷17\frac{7}{4} \div \frac{1}{7}, 82÷415\frac{8}{2} \div \frac{4}{15}, 15÷19\frac{1}{5} \div \frac{1}{9}, 16÷1112\frac{1}{6} \div \frac{11}{12}, 323÷1383\frac{2}{3} \div 1\frac{3}{8}

(i)
Answer

277\frac{27}{7}

(ii)
Answer

74\frac{7}{4}

(iii)
Answer

1

(iv)
Answer

1

(v)
Answer

169\frac{16}{9}

(vi)
Answer

494\frac{49}{4}

(vii)
Answer

15

(viii)
Answer

95\frac{9}{5}

(ix)
Answer

211\frac{2}{11}

(x)
Answer

83\frac{8}{3}

Explanation

(i) 3×97=2773 \times \frac{9}{7} = \frac{27}{7} (ii) 144×12=148=74\frac{14}{4} \times \frac{1}{2} = \frac{14}{8} = \frac{7}{4} (iii) 23×32=1\frac{2}{3} \times \frac{3}{2} = 1 (iv) 146×37=4242=1\frac{14}{6} \times \frac{3}{7} = \frac{42}{42} = 1 (v) 43×43=169\frac{4}{3} \times \frac{4}{3} = \frac{16}{9} (vi) 74×7=494\frac{7}{4} \times 7 = \frac{49}{4} (vii) 4×154=154 \times \frac{15}{4} = 15 (viii) 15×9=95\frac{1}{5} \times 9 = \frac{9}{5} (ix) 16×1211=1266=211\frac{1}{6} \times \frac{12}{11} = \frac{12}{66} = \frac{2}{11} (x) 113÷118=113×811=83\frac{11}{3} \div \frac{11}{8} = \frac{11}{3} \times \frac{8}{11} = \frac{8}{3}