A water tank is filled from a tap. If the tap is open for 1 hour, 7/10 of the tank gets filled. How much of the tank is filled if the tap is open for (a) 1/3 hour (b) 2/3 hour (c) 3/4 hour (d) 7/10 hour (e) For the tank to be full, how long should the tap be running?

(a) 7/30 of the tank (b) 7/15 of the tank (c) 21/40 of the tank (d) 49/100 of the tank (e) 13/7 hours — (a) 1/3 × 7/10 = 7/30 (b) 2/3 × 7/10 = 14/30 = 7/15 (c) 3/4 × 7/10 = 21/40 (d) 7/10 × 7/10 = 49/100 (e) Time = 1 ÷ 7/10 = 10/7 = 13/7 hours

A water tank is filled from a tap. If the tap is open for 1 hour,…

Question 7 of 20intermediate🔧 ApplyNumerical5 marks

A water tank is filled from a tap. If the tap is open for 1 hour, $\frac{7}{10}$ of the tank gets filled. How much of the tank is filled if the tap is open for (a) $\frac{1}{3}$ hour (b) $\frac{2}{3}$ hour (c) $\frac{3}{4}$ hour (d) $\frac{7}{10}$ hour (e) For the tank to be full, how long should the tap be running?

(a)

Answer

$\frac{7}{30}$ of the tank

(b)

Answer

$\frac{7}{15}$ of the tank

(c)

Answer

$\frac{21}{40}$ of the tank

(d)

Answer

$\frac{49}{100}$ of the tank

(e)

Answer

$1\frac{3}{7}$ hours

Explanation

(a) $\frac{1}{3} \times \frac{7}{10} = \frac{7}{30}$ (b) $\frac{2}{3} \times \frac{7}{10} = \frac{14}{30} = \frac{7}{15}$ (c) $\frac{3}{4} \times \frac{7}{10} = \frac{21}{40}$ (d) $\frac{7}{10} \times \frac{7}{10} = \frac{49}{100}$ (e) Time = $1 \div \frac{7}{10} = \frac{10}{7} = 1\frac{3}{7}$ hours

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