Question 11 of 25beginner🔧 ApplyNumerical2 marks

How many multiples of 9 are there between the numbers 4300 and 4400?

Correct Answer

Step 1: Find first multiple ≥\geq 4300 4300 ÷ 9 = 477.78 First multiple ≥\geq 4300: 478×9478 \times 9 = 4302

Step 2: Find last multiple < 4400 4400 ÷ 9 = 488.89 Last multiple < 4400: 488×9488 \times 9 = 4392

Step 3: Count multiples from 478 to 488 Number of multiples = 488 - 478 + 1 = 11

Answer: There are 11 multiples of 9 between 4300 and 4400. The multiples are: 4302, 4311, 4320, 4329, 4338, 4347, 4356, 4365, 4374, 4383, 4392.

Exercise: Figure it Out (Section 2) | Q: 4 | (Page Page 15)
For More Understanding

Explanation

The chapter discusses counting multiples. To find multiples of 9 between 4300 and 4400: Divide 4300 by 9: 4300 ÷ 9 = 477.78. The first multiple ≥\geq 4300 is 478×9478 \times 9 = 4302. Divide 4400 by 9: 4400 ÷ 9 = 488.89. The last multiple < 4400 is 488×9488 \times 9 = 4392. Number of multiples = 488 - 478 + 1 = 11. The multiples are: 4302, 4311, 4320, 4329, 4338, 4347, 4356, 4365, 4374, 4383, 4392.

Solution Steps

  1. Step 1: Find first multiple ≥\geq 4300: 4300 ÷ 9 = 477.78, so 478×9478 \times 9 = 4302

  2. Step 2: Find last multiple < 4400: 4400 ÷ 9 = 488.89, so 488×9488 \times 9 = 4392

  3. Step 3: Count multiples from 478 to 488: 488 - 478 + 1 = 11

  4. Step 4: List: 4302, 4311, 4320, 4329, 4338, 4347, 4356, 4365, 4374, 4383, 4392

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