Question 3 of 25intermediate🔧 ApplyNumerical4 marks

Find a few numbers that leave a remainder of 2 when divided by 3 and a remainder of 2 when divided by 4. Write an algebraic expression to describe all such numbers.

Correct Answer

Step 1: Numbers with remainder 2 when divided by 3 are of the form 3k+23k + 2. Step 2: Numbers with remainder 2 when divided by 4 are of the form 4m+24m + 2. Step 3: Find the LCM of 3 and 4. LCM(3, 4) = 12 Step 4: Numbers satisfying both conditions are of the form 12n+212n + 2. Step 5: Verification: 2÷3=02 \div 3 = 0 remainder 22, 2÷4=02 \div 4 = 0 remainder 22 14÷3=414 \div 3 = 4 remainder 22, 14÷4=314 \div 4 = 3 remainder 22

Answer: Numbers that satisfy both conditions are 2, 14, 26, 38, 50, 62, ... The algebraic expression for all such numbers is 12n+212n + 2, where nn is any non-negative integer.

Exercise: Figure it Out (Section 1) | Q: 4 | (Page Page 11)
For More Understanding

Explanation

The chapter explains that numbers leaving remainder 2 when divided by 3 are of the form 3k + 2. Numbers leaving remainder 2 when divided by 4 are of the form 4m + 2. To satisfy both conditions simultaneously, we need numbers of the form LCM(3,4) × n + 2 = 12n + 2. Verification: 2 ÷ 3 = 0 remainder 2, 2 ÷ 4 = 0 remainder 2. Similarly, 14 ÷ 3 = 4 remainder 2, 14 ÷ 4 = 3 remainder 2.

Solution Steps

  1. Step 1: Numbers with remainder 2 when divided by 3: 3k + 2

  2. Step 2: Numbers with remainder 2 when divided by 4: 4m + 2

  3. Step 3: Find LCM of 3 and 4 = 12

  4. Step 4: Numbers satisfying both conditions: 12n + 2

  5. Step 5: Examples: n=0 gives 2, n=1 gives 14, n=2 gives 26, etc.