Question 2 of 19beginner🔧 ApplyNumerical2 marks

The sum of four consecutive numbers is 34. What are these numbers?

Correct Answer

Given: The sum of four consecutive numbers is 34.

Formula: Let the four consecutive numbers be n, n+1, n+2, and n+3. Sum = n + (n+1) + (n+2) + (n+3) = 4n + 6

Substitution: 4n + 6 = 34

Calculation: 4n = 28 n = 7

Answer: The numbers are 7, 8, 9, and 10.

Exercise: Figure it Out (Section 1) | Q: 1 | (Chapter: Page 11)
For More Understanding

Explanation

Let the four consecutive numbers be n, n+1, n+2, and n+3. Their sum is n + (n+1) + (n+2) + (n+3) = 4n + 6. Setting this equal to 34: 4n + 6 = 34, so 4n = 28, giving n = 7. Therefore, the numbers are 7, 8, 9, and 10.

Solution Steps

  1. Step 1: Let the four consecutive numbers be n, n+1, n+2, n+3.

  2. Step 2: Write the sum: n + (n+1) + (n+2) + (n+3) = 4n + 6

  3. Step 3: Set up equation: 4n + 6 = 34

  4. Step 4: Solve: 4n = 28, so n = 7

  5. Step 5: The numbers are 7, 8, 9, 10

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