Question 58 of 90beginner🔧 ApplyNumerical2 marks

Nitesh is a scrap dealer. How much would he have paid for (b) 20 kg iron, if he paid ₹200 for every 10 kg of iron?

Correct Answer

Step 1: Cost for 10 kg iron = ₹200 Step 2: 20 kg = 2×102 \times 10 kg Step 3: Total cost = 2 × ₹200 = ₹400 Answer: Nitesh would have paid ₹400 for 20 kg of iron.

Exercise: Let Us Do | Q: 62 | (Chapter: Page 10)
For More Understanding

Explanation

The chapter explains multiplication with weights. Cost for 10 kg = ₹200. 20 kg is double of 10 kg. Cost = ₹200×2200 \times 2 = ₹400. Alternatively: Cost per kg = ₹200 ÷ 10 = ₹20. Total cost = 20 kg × ₹20/kg = ₹400.

Solution Steps

  1. Step 1: Cost for 10 kg iron = ₹200

  2. Step 2: 20 kg = 2×102 \times 10 kg

  3. Step 3: Total cost = 2 × ₹200 = ₹400

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