A restaurant owner uses 5 kg 200 g, 8 kg 900 g, and 12 kg 600 g of onions over 3 days. What is the total weight of onions used by the restaurant owner in 3 days?
Given: 5 kg 200 g, 8 kg 900 g, and 12 kg 600 g of onions used over 3 days.
Calculation: Add kg: 5 + 8 + 12 = 25 kg Add g: 200 + 900 + 600 = 1,700 g = 1 kg 700 g Total = 25 kg + 1 kg 700 g = 26 kg 700 g
Answer: The total weight of onions used in 3 days is 26 kg 700 g.
Explanation
The chapter explains addition of weights. Add 5 kg 200 g, 8 kg 900 g, and 12 kg 600 g. Add kg: 5 + 8 + 12 = 25 kg. Add g: 200 + 900 + 600 = 1,700 g = 1 kg 700 g. Total = 25 kg + 1 kg 700 g = 26 kg 700 g. Alternatively, convert to grams: 5,200 + 8,900 + 12,600 = 26,700 g = 26 kg 700 g.
Solution Steps
Step 1: Add all weights: 5 kg 200 g + 8 kg 900 g + 12 kg 600 g
Step 2: Add kg: 5 + 8 + 12 = 25 kg
Step 3: Add g: 200 + 900 + 600 = 1,700 g = 1 kg 700 g
Step 4: Total = 25 kg + 1 kg 700 g = 26 kg 700 g