Question 28 of 42intermediate🔧 ApplyNumerical6 marks

Set B:

30×100=_____30 \times 100 = \_\_\_\_\_ 30×200=_____30 \times 200 = \_\_\_\_\_ 15×100=_____15 \times 100 = \_\_\_\_\_ 15×200=_____15 \times 200 = \_\_\_\_\_ 30×10=_____30 \times 10 = \_\_\_\_\_ 30×20=_____30 \times 20 = \_\_\_\_\_ 15×10=_____15 \times 10 = \_\_\_\_\_ 15×20=_____15 \times 20 = \_\_\_\_\_ 30×1=_____30 \times 1 = \_\_\_\_\_ 30×2=_____30 \times 2 = \_\_\_\_\_ 15×1=_____15 \times 1 = \_\_\_\_\_ 15×2=_____15 \times 2 = \_\_\_\_\_
Correct Answer

Set B:

30×100=300030 \times 100 = 3000 30×200=600030 \times 200 = 6000 15×100=150015 \times 100 = 1500 15×200=300015 \times 200 = 3000 30×10=30030 \times 10 = 300 30×20=60030 \times 20 = 600 15×10=15015 \times 10 = 150 15×20=30015 \times 20 = 300 30×1=3030 \times 1 = 30 30×2=6030 \times 2 = 60 15×1=1515 \times 1 = 15 15×2=3015 \times 2 = 30
Exercise: Multiples of 100 | Q: 32 | (Page Page 12)
For More Understanding

Explanation

Using the pattern from Set A: When the multiplier is halved (from 30 to 15), the product is halved. When the multiplicand is doubled (from 100 to 200), the product is doubled.

Solution Steps

  1. Step 1: Apply the patterns observed in Set A

  2. Step 2: 30×100=300030 \times 100 = 3000, then 30×200=600030 \times 200 = 6000 (doubled)

  3. Step 3: 15×100=150015 \times 100 = 1500 (half of 3000), 15×200=300015 \times 200 = 3000

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